376,438 views
37 votes
37 votes
Solve sin x = cos x on the closed interval [pi, 3pi/2].​

User DRamentol
by
3.3k points

1 Answer

18 votes
18 votes

Answer: x=5π/4

Explanation:

sin x = cos x

sin^2 x=cos^2 x

sin^2 x+sin^2 x=cos^2 x+sin^2x

2 sin^2 x=1

sin^2 x=1/2

sin x=(1/2)^1/2

sin x=
(√(2))/(2)

x=45 degrees, 225 degrees

x=180/4, 5(180)/4

x=π/4, 5π/4 ==> π<=x<=3π/2

x=5π/4

User Vishnuraj V
by
3.0k points
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