Answer:
![g' = 12.11 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/9jmihze3xsjn8rvml2x89xa4ma6i1oj4cg.png)
Step-by-step explanation:
As we know that the acceleration due to gravity is given as
![g = (GM)/(R^2)](https://img.qammunity.org/2020/formulas/physics/high-school/uav22u2qdhzbc3inyc1tc6yo4v8k27zyak.png)
now for earth we know that
![(GM)/(R^2) = 9.81 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/feap9at51b3zko4nqp4uvquvb73eaj36ox.png)
now if on the surface of another planet we know that the mass is same as that the mass of Earth but radius is 10% less than the radius of Earth
so we have
![r = 0.9 R](https://img.qammunity.org/2020/formulas/physics/high-school/4e4yol9exqyoaty3jkytxrongi2qzuagwf.png)
so we will have
![g' = (GM)/((0.9R)^2)](https://img.qammunity.org/2020/formulas/physics/high-school/75ymafs5zgkhxv5ruurw1aadrups3qeom8.png)
![g' = (GM)/(0.81 R^2)](https://img.qammunity.org/2020/formulas/physics/high-school/2dc4oc59406a3b023qx4rv9ngllvph5th4.png)
![g' = 1.23 * 9.81](https://img.qammunity.org/2020/formulas/physics/high-school/w6gfyuibyyufhxjtgyspelvihg6f4sq417.png)
![g' = 12.11 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/9jmihze3xsjn8rvml2x89xa4ma6i1oj4cg.png)