Number of moles in 31.99g O2 And 176.8g NaCl

asked Mar 23, 2023 4.9k views

8 votes

Number of moles in 31.99g O2
And 176.8g NaCl

by Nerea

8.3k points

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10 votes

#O_2

$\\ \sf\longmapsto No\:of\;moles=(Given\:mass)/(Molar\:mass)$

$\\ \sf\longmapsto No\:of\:moles=(31.99)/(32)$

$\\ \sf\longmapsto No\:of\:moles\approx 1$

#NaCl

$\\ \sf\longmapsto No\:of\:moles=(176.8)/(58.5)$

$\\ \sf\longmapsto No\;of\:moles=3mol$

Denis Ryzhkov answered Mar 28, 2023