Question

Determine the number of moles of iodine that reacts with 50g of aluminum​

Answer 1

Answer: The correct answer is option B i.e., 2.78 mol

Step-by-step explanation:

Aluminium reacts with iodine to form Aluminium iodide

`$2Al(s)+3I_(2)(s) \to Al_(2)I_(6)(s)$`

From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide

We know
`$No.\,of\,moles=(weight)/(molecular\,weight) \\`

For 2 moles of Aluminium,
`$2=(weight)/(27)$\\ $weight=2 * 27=54g$`

3 moles of Iodine reacts with 54 g of Aluminium

? moles of iodine react with 50 g of Aluminium

`$=(3 * 50)/(54) =2.78 mol$`