Answer
given,
hydraulic loading rate = 6 m/h
total Volumetric flow rate = 3 MGD
Effective filtration rate = 5.8 m/h
Production efficiency = 97%
filter cycle duration = 48 h
3 MGD = 3 x 0.04381 = 0.131 m³/s = 471.6 m³/hr

Q = 6 x A_f
471.6 = 6 x A_f
A_f = 78.6
x² = 78.6
x = 8.86 m
b) Production efficiency

..........(1)
eff. filtration rate



from equation (1)
volume of water required for back washing = V_b + V_r
= 676.77 m³