Question

HI I NEED HELP I don’t know what I’m doing wrong but I can seem to simplify this correctly

Answer 1

`\bf 4\sqrt[4]{48}\qquad \begin{cases} 48=&2\cdot 2\cdot 2\cdot 2\cdot 3\\ &2^4\cdot 3 \end{cases}\implies 4\sqrt[4]{2^4\cdot 3}\implies 8\sqrt[4]{3}`

tis a good idea to start off by doing a quick prime factoring of the radicand.