Answer:
0.5m^2/Vs and 0.14m^2/Vs
Step-by-step explanation:
To calculate the mobility of electron and mobility of hole for gallium antimonide we have,
(S)
Where
e= charge of electron
n= number of electrons
p= number of holes
mobility of electron
mobility of holes
electrical conductivity
Making the substitution in (S)
Mobility of electron
![8.9*10^4=(8.7*10^(23)*(-1.602*10^(-19))*\mu_e)+(8.7*10^(23)*(-1.602*10^(-19))*\mu_h)](https://img.qammunity.org/2020/formulas/engineering/college/z7yz6zgg00kff68mz8l9tahkyi85e5zeux.png)
![0.639=\mu_e+\mu_h](https://img.qammunity.org/2020/formulas/engineering/college/3sq4zk7wzw0ui5wgr6fggbdc528eom2fng.png)
Mobility of hole in (S)
![2.3*10^5 = (7.6*10^(22)*(-1.602*10^(-19))*\mu_e)+(1*10^(25)*(-1.602*10^(-19)*\mu_h))](https://img.qammunity.org/2020/formulas/engineering/college/dgatnixx5d2p20g3hbkvdtwe36yx48edjk.png)
![0.1436 = 7.6*10^(-3)\mu_e+\mu_h](https://img.qammunity.org/2020/formulas/engineering/college/5veomrn1h48pcfocgcqtn0le07nejlpdkq.png)
Then, solving the equation:
(1)
(2)
We have,
Mobility of electron
![\mu_e = 0.5m^2/V.s](https://img.qammunity.org/2020/formulas/engineering/college/2oqcg19lpn9uvizfbckl5tbngyk4bpfgyl.png)
Mobility of hole is
![\mu_h = 0.14m^2/V.s](https://img.qammunity.org/2020/formulas/engineering/college/xdzqh1iwzap44all5s6illetvryir5tbf4.png)