Question

Dr. Chuck projects a ball horizontally from a lab bench. The ball lands on a bullseye marked on the floor a horizontal distance away. Compared to the time for the ball to simply drop vertically from the bench, the time in the air for Dr. Chuck's projected ball is?

Answer 1

in both the cases the time will be same

Step-by-step explanation:

As we know that the chunk is projected horizontally

so here the initial speed of the chunk is given as

`v_x = v_o`

`v_y = 0`

now in order to reach the ball to the ground we can say

`h = (1)/(2)gt^2`

so we will have

`t = \sqrt{(2h)/(g)}`

now if another ball is just dropped from the same height then its initial speed is also zero in both direction

so again we have

`y = (1)/(2)gt^2`

`t = \sqrt{(2h)/(g)}`

so we can say that in both the cases the time will be same