Write the equation of the line is perpendicular to the line y=-1/5x+9 and passes through the point -2 ,-2

Question

asked Apr 13, 2020 73.1k views

1 Answer

Yevhen Bobrov · Answer 1 · 2020-04-18T05:26:51+0000

Explanation:

Two straight lines are perpendicular when the product of their slopes is -1.

the given line is
y=9-(x)/(5) .

The slope of line
y=mx+c is
.

So, the slope of
y=9-(x)/(5) is
(-1)/(5) .

Let slope of perpendicular line be
.

$m\textrm{ x }(-1)/(5)=-1$

m=5

The line also passes through
(-2,-2) .

The equation of line is
(y-(-2))=5(x-(-2)) .

y+2=5x+10

∴
y=5x+8 is the line perpendicular to
y=9-(x)/(5) and passing through
(-2,-2) .