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Total freshman = 58. Number of freshman who prefer cheese toppings= 14. Determined the probability that a freshman prefer cheese toppings. Round to the nearest thousandth

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Answer:

The probability that a freshman prefer cheese toppings is 0.241

Explanation:

Probability of any event E =
\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}

Here, let E : Event of choosing cheese toppings

So, the number of favorable outcomes = 14

Total number of outcomes = 58

So,
P(E) =  \frac{\textrm{Number of students who like cheese toppings}}{\textrm{Total number of students}}

or, P(E) =
(14)/(58) = 0.241379

So,the probability that a freshman prefer cheese toppings is 0.241379

Rounding of 0.241379 to the nearest thousandth, we get

Here , in 0.241379 thousandth digit is 3, and 3 < 5,

so the value of P(E) = 0.241

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