Answer:
The probability that a freshman prefer cheese toppings is 0.241
Explanation:
Probability of any event E =
![\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r5rudapavhdpljfou4pbwsxf1oa87w1xuc.png)
Here, let E : Event of choosing cheese toppings
So, the number of favorable outcomes = 14
Total number of outcomes = 58
So,
![P(E) = \frac{\textrm{Number of students who like cheese toppings}}{\textrm{Total number of students}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/3mghig68qk3nrtj6fx1pu6n4a4wcuuayj5.png)
or, P(E) =
![(14)/(58) = 0.241379](https://img.qammunity.org/2020/formulas/mathematics/high-school/v5mxdqnl0vot3fpvjj0elkmqf5bofuj5z5.png)
So,the probability that a freshman prefer cheese toppings is 0.241379
Rounding of 0.241379 to the nearest thousandth, we get
Here , in 0.241379 thousandth digit is 3, and 3 < 5,
so the value of P(E) = 0.241