Answer:
A. 400
Explanation:
Although it seems a difficult at first, this problem can be solved in fairly simple manner. First, write down the equations given by the problem:
![7A + 11B = 250\\8A +22C=600](https://img.qammunity.org/2020/formulas/mathematics/high-school/q27er911321i1dyysgxihor225qopvw60w.png)
There we have 3 unknown values and only 2 equations so it can't be solved as a common system problem. However, if we double the first equation and add it to the second one, it yields:
![8A + 22C +14 A + 22B=600 + 500\\22A+22B+22C = 1100\\A+B+C = 50](https://img.qammunity.org/2020/formulas/mathematics/high-school/sfibqv9xjqonbypk8r3yp2nwwjuic6qpyr.png)
Therefore, one machine A, one Machine B, and one Machine C produce 50 widgets per hour, so in one 8-hour day they produce:
![P= 8 * 50 = 400](https://img.qammunity.org/2020/formulas/mathematics/high-school/b4uu03sbpu9j6krlmsavgxnygn0c4d52jo.png)