55.0k views
0 votes
Which two values of x are roots of the polynomial below?
x2-11x + 15

1 Answer

2 votes

The two values of roots of the polynomial
x^(2)-11 x+15 are
(11+√(61))/(2) \text { or } (11-√(61))/(2)

Solution:

Given, polynomial expression is
x^(2)-11 x+15

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.


x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a}

Given that
x^(2)-11 x+15

Here a = 1, b = -11 and c = 15

On substituting the values we get,


x=\frac{-(-11) \pm \sqrt{(-11)^(2)-4 * 1 * 15}}{2 * 1}


\begin{array}{l}{x=(11 \pm √(121-60))/(2)} \\\\ {x=(11 \pm √(61))/(2)} \\\\ {x=(11+√(61))/(2) \text { or } (11-√(61))/(2)}\end{array}

Hence, the roots of given polynomial are
(11+√(61))/(2) \text { or } (11-√(61))/(2)

User Mayid
by
6.2k points