Answer:
17.21kW and 13.97kW
Step-by-step explanation:
To solve this question we have two data that are provided to us and correspond to the Enthalpy.

The energy in mass and enthalpy terms is given by.

Where the variables are,
- m=mass flow rate
- h= Enthalpy of refrigerant at the compressor
We only proceed to replace the values.

Energy transfer rate by mass in the compressor is 13.97kW
Being analogs for the other part of the cycle,

Substituing,

Energy transfer rate by mass out of the compressor is 17.21 kW