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A horizontal force of magnitude 356 N is employed to push a 78.0-kg block a distance of 18.6 m on a rough horizontal surface. If the block moves at a constant speed, (a) What is the work done by the 356-N force? (b) What is the coefficient of kinetic friction between the block and the rough surface?

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Answer:

6621.6 Joule

0.46525

Step-by-step explanation:

F = Force = 356 N

s = Displacement = 18.6 m

m = Mass of block = 78 kg

Work done


W=F* s\\\Rightarrow W=356* 18.6\\\Rightarrow W=6621.6\ J

The work done by the horizontal force is 6621.6 Joule


F=\mu mg\\\Rightarrow \mu=(F)/(mg)\\\Rightarrow \mu=(356)/(78* 9.81)\\\Rightarrow \mu=0.46525

The coefficient of friction between the block and the rough surface is 0.46525

User Jordan Duncan
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