Answer:
6621.6 Joule
0.46525
Step-by-step explanation:
F = Force = 356 N
s = Displacement = 18.6 m
m = Mass of block = 78 kg
Work done
![W=F* s\\\Rightarrow W=356* 18.6\\\Rightarrow W=6621.6\ J](https://img.qammunity.org/2020/formulas/physics/college/g6dv858ebkuu39dep3mmxzf7ggspws59m5.png)
The work done by the horizontal force is 6621.6 Joule
![F=\mu mg\\\Rightarrow \mu=(F)/(mg)\\\Rightarrow \mu=(356)/(78* 9.81)\\\Rightarrow \mu=0.46525](https://img.qammunity.org/2020/formulas/physics/college/y1w6xakckejbw9b3z9bslyaai9f4ng7117.png)
The coefficient of friction between the block and the rough surface is 0.46525