Question

A Plane has a takeoff speed of 150 m/s and requires 1500m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed.

Answer 1

The acceleration of the plane and the time required to reach this speed is (a)= 7.5
`m/sec^2` and time(t) = 20 seconds

Explanation:

Given data Initial velocity
`(V_i)` = 0

Final velocity (
`V_f`) = 150 m/second

Distance (d) = 1500 m

We have the formula,
`$\mathrm{V}_{\mathrm{f}}^(2)=\mathrm{V}_{\mathrm{i}}^(2)+2 \mathrm{ad}$`

which gives
`150^2` = 0+2a(1500)

22500 = 3000 a

acceleration (a) = 7.5
`m/s^2`

`$\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\mathrm{i}}+\mathrm{at}$`

150 = 7.5 t

t= 150/7.5 = 20

t = 20 seconds.