Answer:

As seen in graph, there is an open circle on 0, and it goes out left and right.
Option C is correct option.
Explanation:
We need to draw the graph for the solution of the open sentence

First we will solve the inequality:

Adding -3 on both sides

We know that

So, we have

Now, the graph is attached in the figure below
As seen in graph, there is an open circle on 0, and it goes out left and right.
Option C is correct option.