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18. A set of data has a sample mean of 65.4 and a standard deviation of 1.2. If the sample size is 45, what is the 99% confidence interval of this data?

A. 65.10 and 65.70
B. 65.33 and 65.47
C. 65.05 and 65.75
D. 64.94 and 65.86

User Master Bee
by
8.2k points

2 Answers

11 votes

Answer:

the answer is, 64.94 and 65.86

Explanation:

User Dispix
by
8.1k points
6 votes

Given:

Sample mean = 65.4

Standard deviation = 1.2

Sample size = 45

Confidence level = 99%

To find:

The confidence interval.

Solution:

The formula for confidence interval is


CI=\overline{x}\pm z^*(s)/(√(n))

where,
\overline{x} is sample mean, z* is confidence value, s is standard deviation and n is sample size.

Confidence value or z-value at 99% = 2.58

Putting the given in the above formula, we get


CI=65.4\pm 2.58* (1.2)/(√(45))


CI=65.4\pm 0.46


CI=65.4-0.46\text{ and }CI=65.4+0.46


CI=64.94\text{ and }65.86

Therefore, the correct option is D.

User Shadowarcher
by
7.8k points

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