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9 votes
What is the difference in

momentum between an 87.2 kg
football player running 2.87 m/s and
a 0.0520 kg bullet moving 789 m/s?

What is the difference in momentum between an 87.2 kg football player running 2.87 m-example-1
User Shareeta
by
5.1k points

2 Answers

10 votes

Answer:

209.236

Step-by-step explanation:

Order of Operations: PEMDAS

"Please excuse my dear Aunt Sally"

Parentheses, exponents, multiplication, division, addition and subtraction

First use p=mv

Player:(plug in the data)

= 87.2*2.87

= 250.264

Bullet : (do the same)

Then subtract Bullet-Player =209.236

User Zglin
by
5.3k points
9 votes

Answer:

209.236 kg · m/s

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Physics

Momentum

Momentum Formula: P = mv

  • P is momentum (in kg · m/s)
  • m is mass (in kg)
  • v is velocity (in m/s)

Step-by-step explanation:

Step 1: Define

m₁ = 87.2 kg

v₁ = 2.87 m/s

m₂ = 0.0520 kg

v₂ = 789 m/s

Step 2: Find Momentums

Football Player

  1. Substitute [MF]: P = (87.2 kg)(2.87 m/s)
  2. Multiply: P = 250.264 kg · m/s

Bullet

  1. Substitute [MF]: P = (0.0520 kg)(789 m/s)
  2. Multiply: P = 41.028 kg · m/s

Step 3: Find difference

  1. Define equation: P₁ - P₂
  2. Substitute: 250.264 kg · m/s - 41.028 kg · m/s
  3. Subtract: 209.236 kg · m/s
User Jan Beck
by
5.5k points