The number of adults and children who attended the dinner is 60 and 40 respectively.
How many adults and how many children attended the dinner?
Let
Number of adults = x
Number of children = y
x + y = 100. (1)
x + 1/2y = 80. (2)
Subtract (2) from (1)
y - 1/2y = 100 - 80
1/2y = 20
Divide both sides by 1/2
y = 20 ÷ 1/2
y = 20 × 2/1
y = 40
Substitute y into (1)
x + y = 100
x + 40 = 100
x = 100 - 40
x = 60
Therefore, x equals 60 and y equals 40