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What is the perimeter of the rectangle shown on the coordinate plane, to the nearest tenth of a unit?

12.7 units

16.9 units

24.0 units

33.9 units

What is the perimeter of the rectangle shown on the coordinate plane, to the nearest-example-1
User Shua
by
9.6k points

2 Answers

5 votes

Answer:

33.9

Explanation:

User Rynhe
by
8.3k points
7 votes

Answer:


P=33.9\ units

Explanation:

we know that

The perimeter of a rectangle is equal to


P=2(L+W)

where

L is the length of rectangle

W is the width of rectangle

Let


A(-3,-4),B(-6,-1),C(3,8),D(6,5)

Remember that


W=AB=CD\\L=BC=AD

the formula to calculate the distance between two points is equal to


d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}

step 1

Find the distance AB


A(-3,-4),B(-6,-1)

substitute in the formula


d=\sqrt{(-1+4)^(2)+(-6+3)^(2)}


d=\sqrt{(3)^(2)+(-3)^(2)}


d_A_B=√(18)=4.24\ units

step 2

Find the distance BC


B(-6,-1),C(3,8)

substitute in the formula


d=\sqrt{(8+1)^(2)+(3+6)^(2)}


d=\sqrt{(9)^(2)+(9)^(2)}


d_B_C=√(162)=12.73\ units

step 3

Find the perimeter


P=2(12.73+4.24)


P=33.94\ units

Round to the nearest tenth


P=33.9\ units

User Tomy
by
8.0k points

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