Question

the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations that could be used to determine the dimensions in feet of the volleyball court

Answer 1

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

`A=xy`

`A=1,800\ ft^2`

so

`1,800=xy` ----> equation A

`x=2y` -----> equation B

substitute equation B in equation A

`1,800=(2y)y`

`1,800=2y^2`

Solve for y

Simplify

`900=y^2`

take square root both sides

`y=30\ ft`

Find the value of x

`x=2y`

substitute the value of y

`x=2(30)=60\ ft`

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft