Question

Calculate the root mean square velocity and kinetic energy of CO, CO2, and SO3 at 286 K. Calculate the root mean square velocity and kinetic energy of CO, CO2, and SO3 at 286 K . Calculate the kinetic energy of CO at 286 K .

Answer 1

`KE=3566.706J/mol\\v_(rms,CO)=504.74m/s\\v_(rms,CO_2)=402.65m/s\\v_(rms,SO_3)=298.61m/s`

Step-by-step explanation:

Hello,

Kinetic energy is computed for all the gases as follows, since it does not depend on a particular property of the gas:

`KE=(3)/(2) RT=(3)/(2) *8.314*(J)/(mol*K) *286K=3566.706J/mol`

On the other hand, root mean square velocities for each compound depend on their molecular mass and are computed as follows:

`v_(rms,i)=\sqrt{(3RT)/(M) } \\v_(rms,CO)=\sqrt{(3*8.314(J)/(mol*K) *286K)/(0.028kg/mol) } =504.74m/s\\v_(rms,CO_2)=\sqrt{(3*8.314(J)/(mol*K) *286K)/(0.044kg/mol) } =402.65m/s\\v_(rms,SO_3)=\sqrt{(3*8.314(J)/(mol*K) *286K)/(0.080kg/mol) } =298.61m/s`

Best regards.