Question

What is the mass of Silver in 3.45g AgS?

Answer 1

The mass of silver in 3.45g AgS is 2.65g.

Step-by-step explanation:

To determine the mass of silver in 3.45g AgS, we need to convert the mass of AgS to moles using its molar mass and then calculate the mass of silver. AgS is composed of one silver atom (Ag) and one sulfur atom (S), so its molar mass is the sum of the atomic masses of Ag and S. The atomic mass of Ag is 107.87 g/mol, and the atomic mass of S is 32.07 g/mol. Therefore, the molar mass of AgS is 107.87 g/mol + 32.07 g/mol = 139.94 g/mol.

To convert the mass of AgS to moles, we divide the given mass (3.45g) by the molar mass of AgS (139.94 g/mol).

moles of AgS = mass of AgS / molar mass of AgS = 3.45g / 139.94 g/mol = 0.0246 mol

Since AgS contains one silver atom per molecule, the number of moles of silver is also 0.0246 mol.

To calculate the mass of silver in 0.0246 mol, we multiply the number of moles by the molar mass of silver (107.87 g/mol).

mass of silver = moles of silver * molar mass of silver = 0.0246 mol * 107.87 g/mol = 2.65 g

Therefore, the mass of silver in 3.45g AgS is 2.65g.

Answer 2

Mass = 2.59 g

Step-by-step explanation:

Given data:

Mass of AgS = 3.45 g

Mass of silver = ?

Solution:

Number of moles of AgS:

Number of moles = mass/molar mass

Number of moles = 3.45 g/ 139.93 g/mol

Number of moles = 0.024 mol

1 mole of AgS contain 1 mole of Ag.

0.024 mol contain 0.024 mol of Ag.

Mass of silver:

Mass = number of moles × molar mass

Mass = 0.024 mol × 107.86 g/mol

Mass = 2.59 g