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You want to determine the lower control line for a p-chart for quality control purposes. You take several samples of a size of 50 items in your production process. From the samples you determine the fraction defective is 0.006 and the standard deviation is 0.001. If the desired confidence level is 99.7 percent, which of the following is the resulting LCL value for the line?

A. 0.001
B. 0.002
C. 0.003
D. 0.004
E. None of these

1 Answer

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Answer: C. 0.003

Explanation:

The LCl value of the line for 99.7% confidence level is given by :-


\mu-3\sigma , where
\mu is population mean and
\sigma is standard deviation.

As per given we have,


\mu=0.006\\\\\sigma=0.001

Then, the LCL value for the line is given by :-


0.006-3(0.001)=0.003

Hence, the resulting LCL value for the line is 0.003.

User Sevval Kahraman
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