Answer:
![(12)/(51)\cong(4)/(17)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ab3n2v7ini6bdv3ivyka40mtqfefd4tyu0.png)
Explanation:
You have 52 cards in a deck and 13 cards of each suit.
The probability of picking a diamond in a complete deck of cards is:
![\frac {13}{52}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2dkh07h8sfyq99c6n14bz2axnszzclgb05.png)
Or the probability is 13 put of 52.
Since you took out 1 diamond card already there would be only 51 cards left and 12 diamond cards left. So you would have a probability of:
![(12)/(51)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ro3w11ag51dbeoaq9eivotdl362fzao9zg.png)
If we simplify it you will have a probability of:
![(4)/(17)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kgkbkgxjtmb9ttg0n7xwk41f4u66jd0ddd.png)