Answer:
0.95 atm
Step-by-step explanation:
We are given;
Initial pressure, P1 = 1.0 atm
Initial temperature, T1 =298 K (25°C + 273)
Initial volume, V1 = 0.985 L
Final temperature, T2 = 295 K (22°C + 273)
Final volume, V2 = 1.030 L
We are required to find final air pressure;
Using the combined gas law;
![(P1V1)/(T1) =(P2V2)/(T2)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/7z7w639qd3tf5djjg2s0b976t3a9vi3rq1.png)
To get, P2 ;
![P2=(P1V1T2)/(T1V2)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/u9oss33ga5o142rl0rahwfjugmt837rga9.png)
![P2=((1.0)(0.985L)(295))/((1.030)(298))](https://img.qammunity.org/2020/formulas/chemistry/middle-school/3loi5l4oxenylr4ixxa40fox3p38g2bbia.png)
![P2 = 0.947 atm](https://img.qammunity.org/2020/formulas/chemistry/middle-school/7nq98wijm31o9898ngroq6sj540rh18p5y.png)
= 0.95 atm
Therefore, the air pressure at the top of the mountain is 0.95 atm