3.1k views
0 votes
How do you solve this equation 4-2(v-6)=-8

User RaedMarji
by
8.3k points

2 Answers

2 votes
I couldn’t really crop the whole pic for the answer but like , at the begginimg you have to Distribute -2 through the parenthesis , so it’s gonna be “4-2v+12=8” and then you have to add so it’s gonna be “16-2v=8” now you Move constant to the right side and change its sign soo, “ -2v=8-16” then you calculate them difference which is “-2v=-8” after you Divide both sides of the equation by -2 and the whole think would equal “V=4”
How do you solve this equation 4-2(v-6)=-8-example-1
User Sonu Kumar
by
8.5k points
5 votes

Answer:

first, subtract 4 from each side of the equation to isolate the term with parenthesis while keeping the equation balanced:

−4+4−2(v−6)=−4−8

0−2(v−6)=−12

−2(v−6)=−12

Next, divide each side of the equation by −2 to eliminate the need for parenthesis while keeping the equation balanced:

−2(v−6)−2=−12−2

−2

(v−6)−2

=6

v−6=6

Then, add 6 to each side of the equation to solve for v term while keeping the equation balanced:

v−6+6=6+6

v−0=12

v=12

User Cheeken
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories