Question

A(n) 93 kg clock initially at rest on a horizontal floor requires a(n) 617 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 528 N keeps it moving with a constant velocity. The acceleration of gravity is 9.81 m/s 2 . a) Find µs between the clock and the floor

Answer 1

`\mu_s = 0.676`

Step-by-step explanation:

As we know that the force required to move the clock from rest position must be equal to the maximum limiting friction

So we will have

`F = F_f`

now we know that

`F_f = \mu_s Mg`

here we will have

`F = 617 N`

`m = 93 kg`

now from above formula we will have

`617 = \mu_s (93)(9.81)`

`\mu_s = 0.676`