Answer:
Caffeine remains in Doug’s system after n hours, c(n) = 130 x 0.88ⁿ mg
Explanation:
Doug drank a soda with 130 mg of caffeine.
Caffeine drank = 130 mg
Each hour, the caffeine in the body diminishes by about 12%.
Reduction of caffeine per hour = 12 %
Let c(n) be the caffeine remains in Doug’s system after n hours.
![\texttt{Caffeine remaining in Doug’s system after 1 hour =}130-(12)/(100)* 130=0.88^1* 130mg\\\\\texttt{Caffeine remaining in Doug’s system after 2 hours =}0.88^2* 130mg\\\\\texttt{Caffeine remaining in Doug’s system after 3 hours =}0.88^3* 130mg\\\\\texttt{Caffeine remaining in Doug’s system after n hours =}0.88^n* 130mg](https://img.qammunity.org/2020/formulas/mathematics/high-school/al51e4qxe73ozieth56a6bc0hx43jkpok4.png)
Caffeine remains in Doug’s system after n hours, c(n) = 130 x 0.88ⁿ mg