Question

Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?

It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.

Answer 1

no solution

Explanation:

Answer 2

It has no solution.

Explanation:

The given equation is

`(3)/(4z)-(1)/(4z+1)=(2)/(4z+1)`

We multiply through with
`4z(4z+1)`

`4z(4z+1)*(3)/(4z)-4z(4z+1)*(1)/(4z+1)=4z(4z+1)*(2)/(4z+1)`

`3(4z+1)-4z=8z`

`12z+3-4z=8z`

`12z-4z-8z=-3`

`0=-3`

This is never true.

Therefore the equation has n solution