Answer:
Intial Value: f(t) = 2 , Exponential Growth
Explanation:
To find the initial value, all we have to do is find the value of f(t) at t = 0
In this case the given equation becomes
![f(t) = 2((5)/(3))^0](https://img.qammunity.org/2020/formulas/mathematics/high-school/og8aevzs7riob0f9kboqs7e94g4zprm5kt.png)
from the law of indices we know that any number with the power 0 is equal to 1 (except 0 with the power 0)
![a^0 = 1](https://img.qammunity.org/2020/formulas/mathematics/college/7xp57v64qrpmd45eqgi5t8j99s98a9eiys.png)
hence the above equation becomes
![f(t) = 2(1)\\ f(t) = 2](https://img.qammunity.org/2020/formulas/mathematics/high-school/xcv7kzr6bdatvn2qn0e5abheqfm6prwbxm.png)
so the initial value is 2.
To find out whether this is exponential growth or exponential decay we need to see whether the base value of the power t is less than 1 or greater than 1, i.e. from
![((5)/(3) )^t](https://img.qammunity.org/2020/formulas/mathematics/high-school/k0053edqxuyzfaeu8ueu7x3gq4hrz0m7lg.png)
is
> 1 or
< 1
if the value is greater, then with each increment in power, the total value will increase while if it is less than 1 then with each increment in power the total value will decrease.
Hence since
> 1 then this is an exponential growth