Question

Based on all student records at Camford University, students spend an average of 5.80 hours per week playing organized sports. The population’s standard deviation is 3.50 hours per week. Based on a sample of 64 students, Healthy Lifestyles Incorporated (HLI) would like to apply the central limit theorem to make various estimates. Compute the standard error of the sample mean.

Answer 1

0.4375

Explanation:

Data provided in the question:

Average time spent per week on playing organized sport, μ = 5.80 hours

Standard deviation of the population, σ = 3.50 hours per week

Total number of students in the sample, n = 64

Now,

The standard error of the sample mean =
`(\sigma)/(√(n))`

on substituting the respective values, we get

The standard error of the sample mean =
`(3.50)/(√(64))`

or

The standard error of the sample mean = 0.4375