Answer:
Step-by-step explanation:
Given
Force by first child is
![F_1=75 N](https://img.qammunity.org/2020/formulas/physics/high-school/t5ir3iw6wx9tkijlg8t4qdq3um68ccsne6.png)
Force by second child
![F_2=90 N](https://img.qammunity.org/2020/formulas/physics/high-school/h5mjrp8o37nohu1x3c3fwco8qj10mblcyz.png)
mass of third child and cart is 29 kg
If sufficient force is provided then system tends to change its current state i.e. starts moving
Net Force on system
![=F_2-F_1-f_r=90-75-12=3 N](https://img.qammunity.org/2020/formulas/physics/high-school/cuw0ym2jf7uclvyfrxy6zgnfks3xrkyuwy.png)
net acceleration
![=(F)/(m)=(3)/(29)=0.103 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/fl6bnswla5c5rcpflkfwey1c8lcnmnt10p.png)
If friction force is 15 N then the system would have been in rest as
![F_(net)=0](https://img.qammunity.org/2020/formulas/physics/high-school/kszlmrwwmryfnbfxbk4zunk43g5qm15pml.png)