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A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10m s -2 , with what velocity will it strike the ground? After what time will it strike the Ground?

User Axalix
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1 Answer

9 votes

Height,h= 20m

"gently dropped" means initial velocity, u, =0m/s

Uniform acceleration, g=10m/s²

using the formula v²=u²+2gs

Substituting, v²=0²+2*10*20

v²=400

v=


√(400)

v=20m/s

Time, t at which is strike the ground

using the formula v=u+at

Substituting, 20=0+10t

20=10t

t=2s

This means that the bank strike the ground with a velocity of 20m/s in 2s.

User Riccardo Manzan
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