Answer:
The equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6 will be:
Explanation:
Given
We know that the slope-intercept form of the line equation
y = mx+b
where
substituting m = 6 and the point (3, -4) in the slope-intercept form of the line equation to determine the y-intercept b
y = mx+b
-4 = 6(3) + b
-4 = 18 + b
switch sides
b = -4 - 18
b = -22
now substituting m = 6 and the b = -22 in the slope-intercept form of the line equation
y = mx+b
y = 6x + (-22)
y = 6x - 22
Therefore, the equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6 will be: