Question

Figure ABCD is a trapezoid. What are the values of x and y

Answer 1

360= 2x+3y+(x-12)+(y+20)

360= 3x+4y+8

352=3x+4y

352-3x=4y

88-3x/4=y

352-4y=3x

117 1/3 -4y/3=x

I'm proabably wrong, but I tried.

Answer 2

Answer : The value of x and y are, 64° and 50° respectively.

Step-by-step explanation :

As we know that, ABCD is a trapezium and AB || CD. So, the sum of opposite angles are 180°

`\angle A+\angle D=180^o`

Given:

`\angle A=2x^o\\\\\angle D=(x-12)^o`

`\angle A+\angle D=180^o`

`2x^o+(x-12)^o=180^o`

`3x^o-12^o=180^o`

`3x^o=192^o`

`x=64^o`

and,

Given:

`\angle B=3y^o\\\\\angle C=(y+20)^o`

`\angle A+\angle D=180^o`

`3y^o+(y+20)^o=180^o`

`4y^o+20^o=180^o`

`4y^o=200^o`

`y=50^o`

Thus, the value of x and y are, 64° and 50° respectively.