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(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500 - μC charge and flies due west at a speed of 660 m/s over the Earth’s south magnetic pole, where the 8.00 10 -T 5  magnetic field points straight up. What are the direction and the magnitude of the magnetic force on the plane? (b) Discuss whether the value obtained in part (a) implies this is a significant or negligible effect.

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6 votes

(a)
2.64\cdot 10^(-8) N north

We can treat the aircraft as a single point charge moving in a magnetic field. In this case, the magnetic force exerted on the plane is


F=qvB sin \theta

where


q=0.500 \mu C = 0.500\cdot 10^(-6) C is the charge on the plane

v = 660 m/s is the velocity


B=8.00\cdot 10^(-5) T is the magnitude of the magnetic field


\theta=90^(\circ) is the angle between the direction of motion of the jet and of the magnetic field

Substituting,


F=(0.5\cdot 10^(-6))(660)(8.0\cdot 10^(-5))=2.64\cdot 10^(-8) N

The direction can be found by using Fleming's left hand rule. We have:

- index finger: magnetic field direction (straight up)

- middle finger: velocity of the plane (due west)

- force: thumb --> north

(b) Not negligible

As we can see from part (a), the magnitude of the force is not really big, so the effects are negligible.

For instance, we can compare this force with the weight of a plane. If we take a Boeing 737, its mass is about 80,000 kg, so its weight is


W=mg=(80000)(9.8)=784,000 N

As we can see, this is several orders of magnitude bigger than the magnetic force calculated at point (a), so the effects of the magnetic force are negligible.

User Adam Eliezerov
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