Question

Originally, each face of a pyramid shown to the right was a triangle with the dimensions shown. How far was a corner of the base from the pyramid’s top

Answer 1

The distance of the corner of the base from the top of a pyramid would be = 705.72 feet

How to calculate the corner length of the given pyramid?

To calculate the corner length of the given pyramid the following steps should be taken as follows:

In a right triangle we can apply the Pythagorean Theorem to find out the length of the hypotenuse

c²=b²+a²

where

c is the hypotenuse

a and b are the legs of the right triangle (perpendicular sides)

a= 365

b= 604

c²= 365²+604²

= 133,225+364,816

= 498,041

c=

`√(498041)`

= 705.72

Therefore, the corner of the base is 705.72 feet from the top of the pyramid.

Answer 2

The corner of the base is 705.72 feet from the top of the pyramid

Explanation:

we know that

In a right triangle we can apply the Pythagorean Theorem to find out the length of the hypotenuse

`c^(2)=a^2+b^2`

where

c is the hypotenuse

a and b are the legs of the right triangle (perpendicular sides)

In this problem we have

`a=604\ ft\\b=365\ ft`

substitute

`c^(2)=604^2+365^2`

`c^(2)=498,041`

`c=705.72\ ft`

therefore

The corner of the base is 705.72 feet from the top of the pyramid