Answer:
By a factor of 2
Step-by-step explanation:
The strength of the magnetic field produced by a current-carrying wire is given by

where
is the vacuum permeability
I is the current
r is the distance from the wire
At point A, which is located at a distance
from the wire, the magnetic field strength is

Point B is located at a distance of

from the wire, so the strength of the field at point B is

Or equivalently,

So, the field at A is twice as strong as the field at B.