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MathPhys Please come through i Need HELP

MathPhys Please come through i Need HELP-example-1
User Ben Adam
by
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1 Answer

7 votes

Answer:

4.57 m/s

Step-by-step explanation:

First, find the time it takes to fall 33.1 m. Take down to be positive.

Given:

Δy = 33.1 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(33.1 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 2.60 s

Now find the horizontal velocity needed to travel 11.88 m.

Given:

Δy = 11.88 m

t = 2.60 s

a = 0 m/s²

Find: v₀

Δx = v₀ t + ½ at²

(11.88 m) = v₀ (2.60 s) + ½ (0 m/s²) (2.60 s)²

v₀ = 4.57 m/s

User Jcalz
by
6.0k points