Answer:
31.89%
Explanation:
This situation can be modeled with the Negative Binomial Distribution, where the probability of having r “failures” before k “successes” occur is given by
![\large P(X=k)=\binom{k+r-1}{k}(1-p)^rp^k](https://img.qammunity.org/2020/formulas/mathematics/college/cusdipqa78bdwu6xiq56rwrios518wwgvn.png)
being p the probability that a “success” occurs.
is the number of combinations of m elements taken n at a time.
In the specific case of this problem we have “success” is having a copy with a defect, with probability 0.1, k=1 and r=6 (6 “failures” before 1 “success”).
Computing the formula either by hand or with a computer, we get
![\large P(X=1)=\binom{1+6-1}{1}(1-0.1)^60.1=6*0.9^6*0.1=0.31886\approx 31.89\%](https://img.qammunity.org/2020/formulas/mathematics/college/vrtzdtd1upju4xf73ovqv4czpxkoku1eml.png)