Answer:
31.89%
Explanation:
This situation can be modeled with the Negative Binomial Distribution, where the probability of having r “failures” before k “successes” occur is given by

being p the probability that a “success” occurs.
is the number of combinations of m elements taken n at a time.
In the specific case of this problem we have “success” is having a copy with a defect, with probability 0.1, k=1 and r=6 (6 “failures” before 1 “success”).
Computing the formula either by hand or with a computer, we get
