Question

Solve the equation 25x²+100x+200=0.

Answer 1

`x = -2+2i ,x = -2-2i`

Explanation:

given,

equation 25x²+100x+200=0

dividing the equation by 25 on both side

x²+4x+8=0

using

`x = (-b\pm √(b^2-4ac))/(2a)`

`x = (-4\pm √(4^2-4* 1* 8))/(2)`

`x = (-4+ √(4^2-4* 1* 8))/(2),x = (-4-√(4^2-4* 1* 8))/(2)`

`x = (-4+ √(-16))/(2),x = (-4-√(-16))/(2)`

`x = (-4+ 4i)/(2),x = (-4-4i)/(2)`

`x = -2+2i ,x = -2-2i`