Answer:
![x=(-5*(1+e^(3)) )/(10-e^(3) )](https://img.qammunity.org/2020/formulas/mathematics/high-school/nxcfvxiw19l6n4zdxdpjbkt9azucx729ec.png)
Explanation:
Rewrite the equation, adding 3 to both sides and subtracting log(x-5) from both sides:
![log(10x+5)-log(x-5)=3](https://img.qammunity.org/2020/formulas/mathematics/high-school/ft9x4mgsg5nt6yjktyujya8wqmt4cglj7e.png)
Using the next propierty:
![log((1)/(x) )=-log(x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/w5uo82aoo95frk0k0iy2pd6w5lku8t19x5.png)
![log(10x+5)+log((1)/(x-5))=3](https://img.qammunity.org/2020/formulas/mathematics/high-school/19xh5kv56i4tfye32dte89i13dl9yrynnz.png)
Using this propierty:
![log(x*y)=log(x)+log(y)](https://img.qammunity.org/2020/formulas/mathematics/high-school/1ahlth4ia9dxta2r4r59qv9gvbmx1jaf9a.png)
![log((10x+5)/(x-5))=3](https://img.qammunity.org/2020/formulas/mathematics/high-school/ggxvf17rfs09yx7meaqf8p7xanmj61xy81.png)
Cancel logarithms by taking exp of both sides:
![e^{log((10x+5)/(x-5))} =e^(3) \\(10x+5)/(x-5)=e^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/pg2mh17y215lxfqn8kn2yrnieuv5maq7t4.png)
Multiplying both sides by x-5 and factoring:
![x(10-e^(3) )=-5-5e^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4b2slkqjv2bsng18zl9s1eg1wehampd7zi.png)
Solving for x multiplying both sides by
![10-e^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/el74zwylbgga7h7xdje93la23kheu3ph8i.png)
![x=(-5-5e^(3) )/(10-e^(3) ) =(-5*(1+e^(3)) )/(10-e^(3) )](https://img.qammunity.org/2020/formulas/mathematics/high-school/zkbm0wjgjq7gwht9bnjldojzw7414b9ekl.png)