Question

Solve the following exponential equations.
4^x + 7(2^x) + 12 = 0

Answer 1

Answer:No value of x

Explanation:

Given

`4^x+7(2^x)+12=0`

Let
`2^x=y`

`y^2+7y+12=0`

`y^2+3y+4y+12=0`

`y(y+3)+4(y+3)=0`

`(y+3)(y+4)=0`

`y=-3,-4`

`2^x=-3`

or
`2^x=-4`

so there is no value of x for which
`2^x=-3 or -4`

because minimum value of
`^x=1`