Answer:
5 and 6
Explanation:
We have to first solve the given equation
![10^(x) =432901](https://img.qammunity.org/2020/formulas/mathematics/high-school/w064biv469vlo2hxykznqkafo0ke5avwcg.png)
Now, taking log in the both sides we get,
![log10^(x) = log 432901](https://img.qammunity.org/2020/formulas/mathematics/high-school/heryfrwkc8762uzqsjniq07pnfni2zwvgy.png)
⇒ x log 10=log 432901 {Since we have the logarithm property, log aᵇ =b log a}
⇒ x =log 432901 {Since log 10=1}
⇒ x=5.636.
Therefore, the consecutive integers that are under and over the value of x are 5 and 6. (Answer)