Question

A sealed container filled with argon gas at 35C has a pressure of 832 torr. If the volume of the container is decreased by a factor of two, what will happen to the pressure?

Answer 1

Pressure is increased by a factor of 2

Step-by-step explanation:

`P_(1)`=832 torr and
`P_(2)` is unknown

where
`P_(1)` is initial pressure and
`P_(2)` is the final pressure

`V1 = V`,
`V2 = V/2` where
`V_(1)` and
`V_(2)` are the initial and final volumes respectively

From gas laws

`P_(1)V_(1) = P_(2)V_(2)`

`832* V = P_(2)* \frac {V}{2}`

Pressure
`P_(2) = 1664 torr`

The above pressure of 1664 torr is double the pressure of 832 torr. Therefore, we conclude that the pressure is increased by a factor of 2