Question

Stu and Noke are working with a red food coloring, Red #40. The stock solution has a concentration of 0.0880 M dye. Noke want to makes a concentration of 0.0088 M, exactly one tenth of the original red dye solution strength. What volume of the original 0.0880 M solution should she measure into a 100.0 volumetric flask, to be diluted with water up to the line of the flask? (3 significant digits, unit mL)

2)Stu dilutes the stock 0.0880 M red dye solution (same as the previous question by measuring 25.00 mL with a pipet into a 100.0 mL volumetric flask and then adding water up to the line on the flask. Calculate the new concentration of his diluted solution. (Round to 3 significant digits, unit M)

Answer 1

Answer:

1. Volume of the original 0.0880 M solution should Nok measure into 100 mL volumetric flask is 10.0 mL.

2. The new concentration of diluted solution is 0.0352 M.

Explanation:

1) Concentration of solution given =

Volume of solution red dye solution of 0.0880 M needed =

Required concentration of red dye solution =

Volume of solution red dye solution required=

Volume of the original 0.0880 M solution should Nok measure into 100 mL volumetric flask is 10.0 mL.

2) Concentration of red dye solution given =

Volume of solution red dye solution of 0.0880 M added into volumetric flask=

Required concentration of red dye solution =

Volume of solution red dye solution required=

The new concentration of diluted solution is 0.0352 M.

Step-by-step explanation:

Answer 2

1. Volume of the original 0.0880 M solution should Nok measure into 100 mL volumetric flask is 10.0 mL.

2. The new concentration of diluted solution is 0.0352 M.

Step-by-step explanation:

1) Concentration of solution given =
`M_1=0.0880 M`

Volume of solution red dye solution of 0.0880 M needed =
`V_1`

Required concentration of red dye solution =
`M_2=0.0088 M`

Volume of solution red dye solution required=
`V_2=100 mL`

`M_1V_1=M_2V_2`

`V_1=(0.0088 M* 100 mL)/(0.0880 M)=10.0 mL`

Volume of the original 0.0880 M solution should Nok measure into 100 mL volumetric flask is 10.0 mL.

2) Concentration of red dye solution given =
`M_1=0.0880 M`

Volume of solution red dye solution of 0.0880 M added into volumetric flask=
`V_1=25mL`

Required concentration of red dye solution =
`M_2=?`

Volume of solution red dye solution required=
`V_2=100 mL`

`M_1V_1=M_2V_2`

`M_1=(0.0088 M* 100 mL)/(25 mL)=0.0352 M`

The new concentration of diluted solution is 0.0352 M.